# QA – Placement Quizzes | Numbers, LCM and HCF | Question 5

What should be assigned to # so that 2582#724 is divisible by 11 ?**(A)** 4**(B)** 5**(C)** 6**(D)** 7**Answer:** **(C)****Explanation:** For a number to be divisible by 11, the difference of the sum of numbers at even and odd places should be either 0 or a multiple of 11.

We assume the leftmost digit at position 1.

So, Sum of numbers at even places = 5 + 2 + 7 + 4 = 18

Sum of numbers at odd places = 2 + 8 + # + 2 = 12 + #

Now, to make the number divisible by 11, we equate the sums obtained in the above step.

18 = 12 + #

=> # = 6

Therefore, C (6) is the correct choice.

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