# Line slope calculator 4x+3y=27

**Straight line given by points A[3; 5] and B[6; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.3333x+9

**Canonical form of the line equation:**4x+3y-27 = 0

**Parametric form of the line equation:**

x = 3t+3

y = -4t+5 ; t ∈ R

**Slope:**m = -1.3333

**Slope angle of line: φ =**-53°7'48″ = -0.9273 rad

**X intercept:**x

_{0}= 6.75

**Y intercept:**y

_{0}= q = 9

**Distance line from the origin:**d

_{0}= 5.4

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; -4)

**Normal vector: n =**(4; 3)

**Midpoint of the segment AB: M =**[4.5; 3]

**Perpendicular Bisector equation:**3x-4y-1.5 = 0

**Vector OA = (3; 5) ; |OA| = 5.831**

**Vector OB = (6; 1) ; |OB| = 6.0828**

**Scalar product OA .OB = 23**

**Angle ∠ AOB = 49°34'26″ = 0.8652 rad**